The definition of a conchoid surface is:
rc[u, v] = r[u, v] + k (r[u, v] - P)/Norm[r[u, v] - P] and rc[u, v] = r[u, v] - k (r[u, v] - P)/Norm[r[u, v] - P], P is the pole, k distance and r[u, v] the base surface.
In this notebook we will obtain the conchoid surface of the one-leaf hyperboloid:
{2Sqrt[1+u^2] Cos[v], 3Sqrt[1+u^2]Sin[v], 4 u} with the distance k = 3 and as pole P the {0, 0, 0}.
