Message Boards Message Boards

0
|
6891 Views
|
2 Replies
|
0 Total Likes
View groups...
Share
Share this post:
GROUPS:

Solve .... No more memory available. Mathematica kernel has shut down.

Posted 10 years ago

Hình 1

Solve Equation in Mathematica Version 8,9,10

enter image description here

Why my computer don't run. Help

Attachments:
POSTED BY: Hieu Minh
2 Replies

In[2]:= Reduce[{x^2 + y^2 + 2 x y/(x + y) == 1, x^2 + Sqrt[2010] + Sqrt[2011] y - Sqrt[x + y] == 1}, {x, y}]

        During evaluation of In[2]:= Reduce::useq: The answer found by Reduce contains unsolved equation(s) RowBox[{"{", RowBox[{\(0 == \(\(-2\) + \@2010 + \@2011 - \(\@2011\ \(Root[\(\(\(4021 + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 3 >>\)]\) + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 3 >>\)]\) + \(Power[\(<< 2 >>\)]\)\) &\), 1\)]\)\) + \(Root[\(\(\(4021 + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 3 >>\)]\) + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 2 >>\)]\) + \(Times[\(<< 3 >>\)]\) + \(Power[\(<< 2 >>\)]\)\) &\), 1\)]\)\^2\)\), ",", \(0 == \(\(-2\) + \@2010 + \@2011 - \(\@2011\ \(Root[\(\(\(4021 + \(<< 6 >>\) + \(Power[\(<< 2 >>\)]\)\) &\), 2\)]\)\) + \(Root[\(\(\(4021 + \(<< 6 >>\) + \(Power[\(<< 2 >>\)]\)\) &\), 2\)]\)\^2\)\), ",", \(<< 8 >>\), ",", RowBox[{"0", "==", FractionBox[\(<< 1 >>\), RowBox[{"", \(<< 66 >>\), ""}]]}], ",", \(0 == \(<< 1 >>\)\/735705629768612331158718611476175537815974496201716851830936735778\)}], "}"}]. A likely reason for this is that the solution set depends on branch cuts of Wolfram Language functions. >>

that branch cut thing brings the Reals into mind

In[3]:= Reduce[{x^2 + y^2 + 2 x y/(x + y) == 1,
  x^2 + Sqrt[2010] + Sqrt[2011] y - Sqrt[x + y] == 1}, {x, y}, Reals]
Out[3]= (x == 
    Root[{-2010 + #1^2 &, -2011 + #2^2 &, 
      4021 - 2 #1 - 2 #2 + 2 #1 #2 - 4022 #3 + 2 #2 #3 - 2 #1 #2 #3 + 
        2009 #3^2 + 2 #1 #3^2 + 2 #2 #3^2 - 2 #2 #3^3 + #3^4 &}, {2, 
      2, 1}] && 
   y == Root[{-2010 + #1^2 &, -2011 + #2^2 &, 
      4021 - 2 #1 - 2 #2 + 2 #1 #2 - 4022 #3 + 2 #2 #3 - 2 #1 #2 #3 + 
        2009 #3^2 + 2 #1 #3^2 + 2 #2 #3^2 - 
        2 #2 #3^3 + #3^4 &, -1 + #3 + #4 &}, {2, 2, 1, 1}]) || (x == 
    Root[{-2010 + #1^2 &, -2011 + #2^2 &, 
      4021 - 2 #1 - 2 #2 + 2 #1 #2 - 4022 #3 + 2 #2 #3 - 2 #1 #2 #3 + 
        2009 #3^2 + 2 #1 #3^2 + 2 #2 #3^2 - 2 #2 #3^3 + #3^4 &}, {2, 
      2, 4}] && 
   y == Root[{-2010 + #1^2 &, -2011 + #2^2 &, 
      4021 - 2 #1 - 2 #2 + 2 #1 #2 - 4022 #3 + 2 #2 #3 - 2 #1 #2 #3 + 
        2009 #3^2 + 2 #1 #3^2 + 2 #2 #3^2 - 
        2 #2 #3^3 + #3^4 &, -1 + #3 + #4 &}, {2, 2, 4, 1}])

In[4]:= Reduce[{x^2 + y^2 + 2 x y/(x + y) == 1,
   x^2 + Sqrt[2010] + Sqrt[2011] y - Sqrt[x + y] == 1}, {x, y}, 
  Reals] // N    
Out[4]= (x == 2.04875 && y == -1.04875) || (x == 42.7954 && y == -41.7954)

It could be rewarding if you would pose problems instead of throwing them. Here nobody knows about the area of definition for x and y. It could be interesting (people call this problem posing) whether a Riemann Surface or a point solution is searched for.

Why my computer don't run.

Your computer did not only not run, it did in the opposite run enormously, especially it runs out of resources! So either you deliver more resources to it or you pose the problem to the community.

POSTED BY: Udo Krause
Posted 10 years ago

Put an * between x and y in your xy, eliminate your denominator and your Sqrt[x+y] and then try NSolve or Reduce instead of Solve.

POSTED BY: Bill Simpson
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract