We are working on quadratic equations.
How would I enter x=4/5,x=3,x=-3 and get the equation??
or a=sqrt10,a=-sqrt10n and get the equation?
or x=(-1+_1i)/2 and get the equation?
I'm stummped!! Wolfram has been a nightmare on getting simple algebra help. thank you for any help !
It's really sad how I have tried to use wolfram alpha and rarely get correct answers. I started using other sites and got the answers. I tried to come back for this type of equation but can't find the help anywhere. Thank you again and have a great night.
My mistake, I wrote Sqrt rather than Sqrt ;-)
So I should have written
I just edited my original post to correct this....
I do not believe that there is a way to enter the plus/minus character into Wolfram|Alpha. But when, in algebra, one uses that character it is just a shorthand for writing both cases.
I also note that one would hope that Wolfram|Alpha would give the answer to the statement
quadratic equation with roots 3 and 9
27 - 12 x + x^2
as the result. But apparently the Wolfram|Alpha parser does note recognize this. I sent in a suggestion that it should address this case.
Ok, when I enter the equation in wolfram I don't get the right answer which is a^2-10=0 .
I also cant figure out how to enter x=-1(plus or minus)1i /2 do you know if it will calculate that?
I so appreciate your help David !
If a quadratic equation has two roots --let's call them x1 and x2--then the equation is proportional to
In your example
x1 = Sqrt
x2 = -Sqrt
so the equaiton is
you can expand this out to get the equivalent
x^2 - 10
Just enter the equation:
where a and b are the two roots. That, of course, is the quadratic equation with those roots
I'm sorry but i didn't understand your answer. I have the solution I need the equation from the solution.
do you know how to enter where the plus is over the minus for "plus or minus"
so sorry but I may have not asked the question right.
Here is an example : a=sqrt10, a= - sqrt10 what is the solution to this ?
Thank you !!