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repeated sampling from a list

Philip Cooper
Posted 11 years ago
POSTED BY: Philip Cooper
8 Replies
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Even more efficient would be to use:

f[n_] := Mean /@ RandomChoice[data, {n , 7}]
POSTED BY: Sander Huisman
Philip Cooper
Philip Cooper
Posted 11 years ago

Thank you!
POSTED BY: Philip Cooper

Right you are! I think the coffee hadn't kicked in yet. But the code is right ;-) (I an often code in Mathematica before I can speak sensibly....)
POSTED BY: David Reiss
POSTED BY: David Reiss
Philip Cooper
Philip Cooper
Posted 11 years ago

Wow! Thank you! Cool code! I think you accidentally wrote it backwards? RandomChoice - samples "with replacement", meaning you can draw the same list item more than once in a sample, whereas RandomSample will not (let you). But for (my) statistical purposes, either is fine as the sample is less than 5% of the population (the data set,) and the data set is greater than 30 items.
POSTED BY: Philip Cooper
Philip Cooper
Philip Cooper
Posted 11 years ago

I am extremely grateful, thank you! I changed ListPlot to Histogram. That's what I wanted. And your code looks pretty darn optimum to me! Thanks x 1e6!

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POSTED BY: Philip Cooper

See my comment below about the difference between RandomSample and RandomChoice... it's an important distinction that you need to make to be sure you are calculating what you intend.
POSTED BY: David Reiss

Not sure if its the optimum method but ... f[n_] := Table[Mean[RandomSample[data, 7]], {n}];

ListPlot[f[100]]
POSTED BY: Melvyn Stancliffe
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