The entered point is in the list and is, obviously, the nearest one to itself. If you want three neighbors not the same as the entered point, request four and drop the first one.
Well, I've managed to solve the problem of combining Do with Nearest, but I still get the same point I am looking for its nearest neighbors appearing as its own neighbor.. How to stop that?
Try placing a semicolon between the Do and the Table. Without a termination within a compound statement, white space is interpreted as multiplication of the two statements.
Do
Table
Using a semicolon did not change anything.. Is it possible that Do does not work with Nearest???
