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# how do I find out how wolfram turned my trig equation into sqrt fractions?

Posted 9 years ago
 Fairly simple question, just looking for some help as I work my way through basic physics. ((xcos60)/cos30)sin30 +(xsin60) = 98 turns into (sqrt(3) x)/2+x/(2 sqrt(3)) = 98 so my question is how do i get it to show me the conversion? Also any links to guides for this would be great, I get the idea but I just have trouble converting it between the 2. Thank you for any help, it is much appreciated.
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Posted 9 years ago
 basically I am trying to compare steps in this, which i copied off a handout , brushing up on my math skills I would like to see all the steps, which i cant seem to replicate, mainly from the first equation to the 2nd one, where did that other t2 go? haha i am using X instead of the t2 and i dont use the N but having not a heck of a lot of luck right now getting the step by step to show on wolfram(T2cos60/cos30) sin30 + T2sin60 = 98NThe rest is just algebra...T2 (cos60 sin30/cos30 + sin60) = 98NT2 = 98N/(cos60 sin30/cos30 + sin60)T2 = 98N / 1.155 = 84.9N
Posted 9 years ago
 Oh ,I hadn't realized that it simply was a replacement process at all. Thank you very much for the information. If i wanted it to be a simplified version of what I said solving for X value, with cos and sin still in there, how would I go about that?
Posted 9 years ago
 If i wanted it to be a simplified version of what I said solving for X value, with cos and sin still in there, how would I go about that? One way is not to use numbers for the angles, but symbols. something like Clear[x, y]; ((x Cos[y])/Cos[y/2]) Sin[y/2] + (x Sin[y]) == 98 Now Mathematica can't replace the trig functions with numerical values, since it does not know what the angle y is.
Posted 9 years ago
 ((xcos60)/cos30)sin30 +(xsin60) = 98 turns into (sqrt(3) x)/2+x/(2 sqrt(3)) = 98 You must have typed  ((x Cos[60 Degree])/Cos[30 Degree]) Sin[30 Degree] + (x Sin[60 Degree]) == 98 Mathematica simply evaluated the trig functions in there, since they have known values and replaced them with their values. The result is what comes out 