# Physics thermoelectricity related plot

Posted 8 years ago
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 Why, I cannot see the plot when I type of the following code: In[56]:= << PhysicalConstants (* tick mark used, next to number 1 \ key*) In[57]:= BoltzmannConstant Out[57]= (1.38065*10^-23 Joule)/Kelvin In[58]:= Vt[T_] := BoltzmannConstant*T/ElectronCharge In[111]:= Vt[1] Out[111]= (0.0000861734 Joule)/(Coulomb Kelvin) In[60]:= Ies = 10^-9 (* Unita A Transistor reverse current *) Ic[Vbe_, T_] := Ies*(Exp[Vbe/(Vt[T])] - 1) In[116]:= Plot[Ic[Vbe, 273], {Vbe, 0, 0.7}] 
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Posted 8 years ago
 You might edit in a little note saying what version of Mathematica you are using. The way units were handled was completely changed starting with version 9 and examples for a version you don't have won't be helpful.If you are using version 9 or later then you might compare this with what you showed. And watch for the missing _ in your Ic definition. In[1]:= boltz = UnitConvert[Quantity["BoltzmannConstant"], "Joules"/"Kelvins"] Out[1]= Quantity[1.38065*10^-23, ("Joules")/("Kelvins")] In[2]:= echarge = UnitConvert[Quantity["ElectronCharge"], "Coulombs"] Out[2]= Quantity[1.6021766*10^-19, "Coulombs"] In[3]:= Vt[T_] := boltz*T/echarge In[4]:= Vt[1] Out[4]= Quantity[0.000086173, ("Joules")/("Coulombs" "Kelvins")] In[5]:= Ies = 10^-9 (*Unita A Transistor reverse current*) Out[5]= 1/1000000000 In[6]:= Ic[Vbe_, T_] := Ies*(Exp[Vbe/QuantityMagnitude[Vt[T]]] - 1) In[7]:= Ic[Vbe, 273] Out[7]= (-1 + E^(42.5074 Vbe))/1000000000 In[8]:= Plot[Ic[Vbe, 273], {Vbe, 0, 0.7}] `If you insert PlotRange->All just before the final closing ] of that Plot then you will be able to see the current out to 0.7 volts.Please check this carefully and point out any mistakes that you see. Thank you
Posted 8 years ago
 Please edit your TITLE and make it meaningful and describing your question.Please read the rules of this forum - especially about code formatting - then edit your post and format code properly.
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