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Where can I find a definition of Wolfram Language statements supported?

Posted 9 years ago

I ask because the extent of Wolfram Language support seems completely undocumented.

And this is accepted:

ContourPlot3D[x^2 + y^2 + z^2 ==  1]

Whereas this is not:

ContourPlot3D[x^2 + y^2 + z^2 ==  1,Mesh -> None]

Thanks

POSTED BY: Chris Jordan
9 Replies
Posted 9 years ago

Sorry to be unclear. I want to know the set of of Wolfram Language statements supported.

A plain list will do fine.

POSTED BY: Chris Jordan

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POSTED BY: Simon Cadrin
Posted 9 years ago

Nice, but an an answer to the question would be nicer :)

POSTED BY: Chris Jordan

enter image description here

POSTED BY: Simon Cadrin
Posted 9 years ago

Sam Carrettie added:

Wolfram|Alpha understands mostly short natural language queries

Source, please?

and just simple Wolfram Language syntax.

Where is this subset documented?

For advanced code pieces use free version of Wolfram Programming Cloud.

Thanks, but AFAICT that's missing needed Alpha features like web widgets.

POSTED BY: Chris Jordan

Wolfram|Alpha understands mostly short natural language queries and just simple Wolfram Language syntax. For advanced code pieces use free version of Wolfram Programming Cloud.

POSTED BY: Sam Carrettie
Posted 9 years ago

Wolfram Alpha doesn't understand that either. It responds: "Showing instead result for query: x^2 + y^2 + z^2 == 1".

POSTED BY: Chris Jordan
ContourPlot3D[x^2 + y^2 + z^2 == 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1}, Mesh -> True]
POSTED BY: Simon Cadrin
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