Message Boards Message Boards

0
|
7317 Views
|
2 Replies
|
0 Total Likes
View groups...
Share
Share this post:

interval estimation

Posted 10 years ago

Hello, I would like to ask, I have the following task:

sided interval estimate - OK,

using the test results will be released position P value, - OK

based on the P value set significance level = number - OK

number = derive the interval for location and variability test ..... ???

data = RandomVariate[NormalDistribution[0, 1], 

   300]; (* Generování dat. *)

Needs["HypothesisTesting`"]

TableForm[

 {Text["Oboustranný odhad st?ední hodnoty:"], strh = MeanCI[data],

  Text["Oboustranný odhad rozptylu:"],

  rozpt = VarianceCI[data],

  Text["Oboustranný odhad sm?rodatné odchylky:"], smod = Sqrt[rozpt],

  Text["Hodnota PValue:"],

  polohaP = LocationTest[data, 0, "PValue"],

  Text["Nastavení hladiny významnosti dle PValue:"], 

  hladina = polohaP}] 

Thanks for the advice :)

POSTED BY: Martin Pavlovec
2 Replies

enter image description here

POSTED BY: Simon Cadrin

I'm not sure I understand the question.

Which version of Mathematica are you using?

For versions 9 and 10, you probably don't want to use the HypothesisTesting` package. There are new functions which are easier to use.

POSTED BY: Sean Clarke
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract