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Start a BodePlot at -180 degree phase?

POSTED BY: Giovanni Ferdina
2 Replies
Posted 9 years ago
POSTED BY: Zhe Hu

At low frequencies the phase is Arg[-20]/Degree-90 = 90 which is what is seen on the BodePlot.

You may desire that the phase of -20 be considered as -180 degrees instead. In that case just tweak the PhaseRange .

BodePlot[(4 (s - 20))/(s (s + 0.8)), PlotLayout -> "Phase", PhaseRange -> {-((3 [Pi])/2) - 2 [Pi], -((3 [Pi])/2)}]

enter image description here

POSTED BY: Suba Thomas
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