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Yes. if n=-1 when x^(2+3i/10) (X+xi)^(Y+yi)=e^((Y+yi)*Ln(X+xi)) Ln(X+xi)=ln((X^2+x^2)^(1/2))+i(f+2Pn), tg(f)=x/X, n=0,1,2... |
Discussions |
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Yes. if n=-1 when x^(2+3i/10) (X+xi)^(Y+yi)=e^((Y+yi)*Ln(X+xi)) Ln(X+xi)=ln((X^2+x^2)^(1/2))+i(f+2Pn), tg(f)=x/X, n=0,1,2... |