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[?] Why does this series have imaginary terms?

Posted 8 years ago

I am trying to construct a series around infinity and I get the following result:

In[14]:= Normal@Series[ Sqrt[2 Pi x] BesselI[3, x]/Exp[x], {x, \[Infinity], 3}, Assumptions -> (x > 0)]
Out[15]=(-I + E^(2*x)*(1 + 945/(128*x^2) - 35/(8*x)) - (945*I)/(128*x^2) - (35*I)/(8*x))/E^(2*x)

Notice that x is assumed real which means that the result should not not have any imaginary terms but it does. What is going on here? And what is the best way to get rid of these terms?

POSTED BY: David Sagan
4 Replies

The asymptotic expansions for modified Bessel functions are inherently complex functions. See asymptotic expansion for I_nu(z) in http://functions.wolfram.com/Bessel-TypeFunctions/BesselI/introductions/Bessels/ShowAll.html

?? ?

POSTED BY: S M Blinder
Posted 8 years ago
POSTED BY: David Sagan

Try:

ComplexExpand@Re@Normal@Series[Sqrt[2 Pi x] BesselI[3, x]/Exp[x], {x, \[Infinity], 3}, Assumptions -> {x > 0}]
POSTED BY: Mariusz Iwaniuk
Posted 8 years ago
POSTED BY: David Sagan
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