How can I plot z as a function of "a"?
z = Table[NIntegrate[Sin[a + b x], {x, -10, 10}], {b, 0, 5, 0.5}, {a, 0, 5, 0.5}]; ListPlot[z, Joined -> True, PlotRange -> All]
Thank you again. This is exactly equal to
F[a_?NumericQ, b_?NumericQ] := NIntegrate[Sin[x^a - x^b], {x, 1, 2}] Plot[F[y, 3.5], {y, 1, 2}]
Why that?
Yes, but this function is just a simple example. My original function is more complicated, so I need NIntegrate.
In[1]:= u = Integrate[Sin[a + b*x], {x, -10, 10}] Out[1]= (2 Sin[a] Sin[10 b])/b
Hey. Thank you a lot. Why did you replace NIntegrate with Integratre?
u = Integrate[Sin[a + b*x], {x, -10, 10}]; {Plot3D[u, {a, 0., 5}, {b, 0.0001, 5}, PlotRange -> All, Mesh -> None, ColorFunction -> Hue, AxesLabel -> {"a", "b", ""}], Plot[u /. b -> 1, {a, 0, 5}, AxesLabel -> Automatic]}