0
|
4110 Views
|
4 Replies
|
2 Total Likes
View groups...
Share
GROUPS:

# Are results exact, or a really good approximation?

Posted 10 years ago
 I have no idea where to post this question!! Here it goes:  If my input is: '((2^756,839)-1) * ((2^1,257,787)-1)' ; Will the result be an excellent approximation(near exact) or the exact answer?
4 Replies
Sort By:
Posted 10 years ago
 This sort of question can be sent directly to the Wolfram|Alpha folks by entering it in the "Give us your feedback" window at the bottom of the page.  (The little slot opens wide when you start typing into it.)
Posted 10 years ago
 Thank you, Szabolcs. With Wolfram|Alpha, the output for  ((2^756,839)-1) * ((2^1,257,787)-1)   says it is a "Decimal approximation". If you keep pressing the "More Digits" button you will eventually reach excellent approximation, then (maybe) exact. When I gave Wolfram|Alpha the input          ((2^756,839)-1) * ((2^1,257,787)-1)   exact  it ran out of time doing the calculation and returned nothing.
Posted 10 years ago
 Mohamed, you should probably make it clear that your question refers to Wolfram|Alpha and not  Mathematica, otherwise people will misunderstand it (like Bruce did). (The original question, deemed off topic for Mathematica.SE,  was here.)
Posted 10 years ago
 The usual rule is exact in, exact out.  Some numerical functions convert exact inputs to the specified approximation. (fyi, omit the commas.) In:= ((2^756839)-1) * ((2^1257787)-1)   // Short                                      Out//Short= 717867916223158231614373981632865219489160<<606398>>95739805181539094888449<<606398>>  means   606398  digits were omitted.  The output is very long. A good starting place is http://reference.wolfram.com/mathematica/tutorial/ExactAndApproximateResults.html.