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Apply a Continued Fraction Operation to a Filter Model

Posted 5 years ago

Hello, Does anyone know of any way to generate a continued fraction from a Filter Model? Thanks.

POSTED BY: Roger B
13 Replies

Please add an explicit example in Mathematica.

POSTED BY: Daniel Lichtblau
Posted 5 years ago

Thanks for your response.

I've pretty much concluded that the only way to work with these analog filter models besides plotting them or running time domain simulations in System Modeller is to extract the zeros and poles, with those form polynomials and a rational transfer function and then manipulate that as one normally does. I was just hoping that I was missing something and that there was a way to extract the transfer function directly for further manipulations.

Thanks.

POSTED BY: Roger B
Posted 5 years ago

If you are looking for the underlying expression you can do the following:

BesselFilterModel[3][ss][[1,1]]

and get

15./(15. + 26.335085835*ss + 18.494313224981806*ss^2 + 
   5.4116591804363505*ss^3)
POSTED BY: Suba Thomas
Posted 5 years ago

Thanks Suba! That saved me a boat load of work. Where in the documentation does it say that?

POSTED BY: Roger B
Posted 5 years ago

Thanks Suba! That saved me a boat load of work. Where in the documentation does it say that?

POSTED BY: Roger B

I was not able to find it in documentation either (I asked Suba to weigh in for that reason).

POSTED BY: Daniel Lichtblau
Posted 5 years ago

I was not able to find it in documentation either (I asked Suba to weigh in for that reason).

POSTED BY: Suba Thomas
Posted 5 years ago

The first one in Properties & Relations [link]

Other occurrences can be found elsewhere as well [link] [link]

POSTED BY: Suba Thomas
Posted 5 years ago

I'm looking at your first link and I'm not seeing it.

POSTED BY: Roger B
Posted 5 years ago

You are not seeing the following?

enter image description here

POSTED BY: Suba Thomas
Posted 5 years ago

I'm looking at your other links and I'm not seeing it there either.

POSTED BY: Roger B
Posted 5 years ago

Oh. Ok. Sorry. Yes. I guess it's there.

POSTED BY: Roger B
Posted 5 years ago

Not a problem.

POSTED BY: Suba Thomas
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