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TransferFunctionModel Question

Posted 11 years ago
Here are three ways to define a transfer function model. From the documentation, it seems to me that all three should produce the same thing. But the third case, which specifies {nunerator, denominator} = {a, b s} seems to result in something different. What is it I am misunderstanding?

Here's the documentation I'm reading:
POSTED BY: David Keith
2 Replies
Posted 11 years ago
Yes!  Thank you very much, David.
(This community is wonderfully useful.)
POSTED BY: David Keith
Posted 11 years ago
If you look at the notes under the section, Details and Options, it says you have to specify num as a matrix... den can be specified as a matrix or just a denominator.

The following works as expected:
In[1]:= TransferFunctionModel[{{{a}}, {{b s}}}, s]
POSTED BY: David G
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