Message Boards Message Boards

1
|
7744 Views
|
2 Replies
|
2 Total Likes
View groups...
Share
Share this post:
GROUPS:

TransferFunctionModel Question

Posted 12 years ago
Here are three ways to define a transfer function model. From the documentation, it seems to me that all three should produce the same thing. But the third case, which specifies {nunerator, denominator} = {a, b s} seems to result in something different. What is it I am misunderstanding?

Here's the documentation I'm reading:
POSTED BY: David Keith
2 Replies
Posted 12 years ago
Yes!  Thank you very much, David.
(This community is wonderfully useful.)
POSTED BY: David Keith
Posted 12 years ago
If you look at the notes under the section, Details and Options, it says you have to specify num as a matrix... den can be specified as a matrix or just a denominator.

The following works as expected:
In[1]:= TransferFunctionModel[{{{a}}, {{b s}}}, s]
POSTED BY: David G
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract