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Solving for an expression in cascades of stages and ladders

Jan Brittenson

Posted 6 years ago

POSTED BY: Jan Brittenson

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Daniel Lichtblau

Daniel Lichtblau, Wolfram Research

Posted 6 years ago

Is the intent to eliminate the variables of interest i.e. `Vout/Vin-><function of remaining variables>`?

POSTED BY: Daniel Lichtblau

Gianluca Gorni

Gianluca Gorni, University of Udine

Posted 6 years ago

A replacement can do something like that, unless I misunderstand you: In[7]:= Vout == Simplify[Vsupply - (Vin - Vbe) ((hfe + 1)/hfe)RC/RE /. Vin -> Vout/DCTransferFunction] Out[7]= Vout == ((1 + hfe) RC (DCTransferFunction Vbe - Vout))/( DCTransferFunction hfe RE) + Vsupply You can leave it to Mathematica to find the replacement with `Solve`: Vout == Simplify[ Vsupply - (Vin - Vbe) ((hfe + 1)/hfe)RC/RE /. Solve[Vout/Vin == DCTransferFunction, Vin][[1]]]

A replacement can do something like that, unless I misunderstand you:

In[7]:= Vout == 
 Simplify[Vsupply - (Vin - Vbe) ((hfe + 1)/hfe)*RC/RE /.
   Vin -> Vout/DCTransferFunction]

Out[7]= Vout == ((1 + hfe) RC (DCTransferFunction Vbe - Vout))/(
  DCTransferFunction hfe RE) + Vsupply

You can leave it to Mathematica to find the replacement with Solve:

Vout == Simplify[
  Vsupply - (Vin - Vbe) ((hfe + 1)/hfe)*RC/RE /. 
   Solve[Vout/Vin == DCTransferFunction, Vin][[1]]]

POSTED BY: Gianluca Gorni

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