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Find Taylor expansion term for a function at a given $n$ and $k$.

Posted 6 years ago
POSTED BY: Wolfram Alpha
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Posted 6 years ago

For me the result in the end is $f(1,\pi)=\frac{1}{3!}(-e^{\pi}-3\pi e^{\pi})(x-1)(x-\pi)^3$

POSTED BY: Wolfram Alpha

I think there's a missing $\frac{1}{n!}$ in your formula, and I think your derivatives aren't correct. At any rate, in Mathematica you can just use SeriesCoefficient:

SeriesCoefficient[Exp[x y] Sin[x^2 y], {x, 1, 1}, {y, Pi, 3}]

1/3 E^? (-3 + ?)

POSTED BY: Carl Woll
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