Group Abstract Group Abstract

Message Boards Message Boards

0
|
5K Views
|
1 Reply
|
1 Total Like
View groups...
Share
Share this post:

How SphericalPlot3D actually works?

Posted 6 years ago
POSTED BY: Robert Poenaru

You are plotting the value of a constant function on the sphere:

In[23]:= Sqrt[Spin2[SPIN, x, y]] // Simplify

Out[23]= 15

This way you get a sphere with radius 15. Your coordinates x,y are not cartesian: they fix a direction in space.

Compare what you get with PolarPlot[15,{theta,0,2Pi}]: this associates with every direction theta a radius with length 15, so that you get a circle with radius 15.

POSTED BY: Gianluca Gorni
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard