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Regarding units of output value

abhishek sharma, ab college
Posted 5 years ago

Hi All, I am using the following command, to find maximum of a function:

FindMaximum[Cos[phi Degree] (1 - 0.4 Sin[5 Degree + phi Degree]^2), phi]

And getting the following Out put:

{0.998309, {phi -> -2.22083}}

I know Mathematica by default use the values of an angle in Radians, therefore, I used the Degree with angles in INPUT.

Now, I am not sure about the value of output given in Mathematica. Whether its' phi=-2.22083 Degree OR -2.22083 Radians?
POSTED BY: abhishek sharma
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Regarding units of output value
POSTED BY: Ian Williams

Yes, you're quite right. My mistake.
POSTED BY: Ian Williams

Yes, you're quite right. My mistake.
POSTED BY: Ian Williams

The result is in terms of degrees. Plot the input expression with phi ranging from -90 to 90 and you will see this.
POSTED BY: Daniel Lichtblau

Sorry, haven't been near my computer for a while. Having checked, I don't think my suggestion works, I wasn't sure that it would - see attached notebook. But the value of phi in your output is definitely in radians.

Thanks for the reply. Can you elaborate : "you could try wrapping the angular variables, x, in Quantity[x,”AngularDegrees”] "

Do you mean I use the command FindMaximum[Cos[phi] (1 - 0.4 Sin[5 Degree + phi]^2), phi "AngularDegrees"]
POSTED BY: abhishek sharma

I’d expect the output to be in radians. All the Degree multiplier does is convert the specified value form degrees to radians. Try typing Degree//N to get its numeric value. If you want to retain the units in the output, you could try wrapping the angular variables, x, in Quantity[x,”AngularDegrees”] - tip, you can generate a nicely formatted version of this Quantity expression by typing ctrl= followed by “x Angular Degrees”. This might return a Quantity result (in this case either radians or angular degrees). I’m not sure whether it would have the desired outcome, but might be worth a go to see what you get.
POSTED BY: Ian Williams

Regarding units of output value
POSTED BY: Ian Williams
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