Message Boards

WOLFRAM COMMUNITY

4213 Views

2 Replies

0 Total Likes

View groups...

Follow this post

Share this post:

GROUPS:

Wolfram Language Units

Why does the 2/pi term appear in the units portion of the calculation below

Edward Davis

Edward Davis, Auburn University

Posted 3 years ago

In[783]= HB[P_, DD_, d_] := 2P/(PiDD*(DD - (DD^2 - d^2)^(1/2))) HB[{500, Quantity[1, "Kilograms"]}, {10, Quantity[1, "Millimeters"]}, {1.62, Quantity[1, "Millimeters"]}] Out[784]= {240.975, Quantity[2/\[Pi], ("Kilograms")/("Millimeters")^2]}

In[783]= 
HB[P_, DD_, d_] := 2*P/(Pi*DD*(DD - (DD^2 - d^2)^(1/2)))
HB[{500, Quantity[1, "Kilograms"]}, {10, Quantity[1, "Millimeters"]}, 
{1.62, Quantity[1, "Millimeters"]}]

Out[784]= {240.975, Quantity[2/\[Pi], ("Kilograms")/("Millimeters")^2]}

POSTED BY: Edward Davis

2 Replies

Sort By:

Rohit Namjoshi

Posted 3 years ago

Hi Edward, Because lists are being passed to `HB` and many operations thread across lists. Pi * {10, Quantity[1, "Millimeters"]} (* {10 \[Pi], Quantity[\[Pi], "Millimeters"]} ) Pass the right quantities instead HB[Quantity[500, "Kilograms"], Quantity[10, "Millimeters"], Quantity[1.62, "Millimeters"]] ( Quantity[240.975, ("Kilograms")/("Millimeters")^2] *)

Hi Edward,

Because lists are being passed to HB and many operations thread across lists.

Pi * {10, Quantity[1, "Millimeters"]}
(* {10 \[Pi], Quantity[\[Pi], "Millimeters"]} *)

Pass the right quantities instead

HB[Quantity[500, "Kilograms"], Quantity[10, "Millimeters"], Quantity[1.62, "Millimeters"]]
(* Quantity[240.975, ("Kilograms")/("Millimeters")^2] *)

POSTED BY: Rohit Namjoshi

Edward Davis

Edward Davis, Auburn University

Posted 3 years ago

Thank you thank you thank you......

POSTED BY: Edward Davis

Reply to this discussion

Reply Preview

Attachments

Remove Add a file to this post

Follow this discussion

or Discard

Group Abstract

Feedback