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Graphics and Visualization Wolfram Language

Plot parametric functions in 3D?

S Long

Posted 4 years ago

I did a 2D plot of the following equation using Mathematica. Could some help me with the right command in Mathematica to convert the output into a 3D model? K0=(K1(α-μ)((αμ)-μ-2))/(2(α+1)*〖(μ+1)〗^2 ) J=K0//.{K1→1,μ→0.02}; L=K0//.{K1→1,μ→0.05}; M=K0//.{K1→1,μ→0.1}; Plot[{J,L,M},{α,0,10},PlotRange→{{-0.5,10},{-1,1.}},PlotStyle→{{Dashed,Blue},{Dashing,Black},{Dashed,Orange},AspectRatio→1.,ImageSize→Large]

I did a 2D plot of the following equation using Mathematica. Could some help me with the right command in Mathematica to convert the output into a 3D model?

K0=(K1*(α-μ)*((α*μ)-μ-2))/(2*(α+1)*〖(μ+1)〗^2 )

J=K0//.{K1→1,μ→0.02};

L=K0//.{K1→1,μ→0.05};

M=K0//.{K1→1,μ→0.1};

Plot[{J,L,M},{α,0,10},PlotRange→{{-0.5,10},{-1,1.}},PlotStyle→{{Dashed,Blue},{Dashing,Black},{Dashed,Orange},AspectRatio→1.,ImageSize→Large]

POSTED BY: S Long

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Hans Milton

Posted 4 years ago

`ParametricPlot3D` will give you a curve in 3D K0 = (K1(\[Alpha] - \[Mu])((\[Alpha]\[Mu]) - \[Mu] - 2))/(2(\[Alpha] + 1)*(\[Mu] + 1)^2) J = K0 /. {K1 -> 1, \[Mu] -> 0.02}; L = K0 /. {K1 -> 1, \[Mu] -> 0.05}; M = K0 /. {K1 -> 1, \[Mu] -> 0.1}; ParametricPlot3D[{J, L, M}, {\[Alpha], 0, 10}]

ParametricPlot3D will give you a curve in 3D

K0 = (K1*(\[Alpha] - \[Mu])*((\[Alpha]*\[Mu]) - \[Mu] - 2))/(2*(\[Alpha] + 1)*(\[Mu] + 1)^2)

J = K0 /. {K1 -> 1, \[Mu] -> 0.02};
L = K0 /. {K1 -> 1, \[Mu] -> 0.05};
M = K0 /. {K1 -> 1, \[Mu] -> 0.1};

ParametricPlot3D[{J, L, M}, {\[Alpha], 0, 10}]

enter image description here