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How to solve equation with arctan in Wolfram|Alpha?

Posted 4 years ago

I'm using the following calculation to find the degree of camber using some measurements:

arctan((AD-BC)/AB)

Using this calculation I get: arctan((32.9-25.4)/381) = 1.128 degrees

My variable is in this exercise is 32.9 so we'll call that X - and I want my degrees to equal 2.4. What should X be to equal approximately 2.4 degrees?

E.g. arctan((x-25.4)/381) = 2.4

I can't for the life of me figure out how to get Wolfram|Alpha to solve an approximation for this!! Any help would be appreciated. Note: I don't require it to be EXACTLY 2.4, just close!

POSTED BY: Matthew Whitney
4 Replies

You probably asking for a solution like this:

NSolve[ArcTan[(x - 25.4), 381] == 2.4, x]

This takes the quadrant into account - refer to the documentation on ArcTan.

POSTED BY: Henrik Schachner

What do you think about this?

angle = ArcTan[a (x - b)]
equation = y == Tan[angle]
Solve[equation, x]

Tan[ArcTan[(x - 25.4)/381]] == Tan[2.4]
POSTED BY: Hans Dolhaine
POSTED BY: Matthew Whitney
Posted 4 years ago
POSTED BY: Bill Nelson
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