# How to solve equation with arctan in Wolfram|Alpha?

Posted 6 months ago
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 I'm using the following calculation to find the degree of camber using some measurements:arctan((AD-BC)/AB)Using this calculation I get: arctan((32.9-25.4)/381) = 1.128 degreesMy variable is in this exercise is 32.9 so we'll call that X - and I want my degrees to equal 2.4. What should X be to equal approximately 2.4 degrees?E.g. arctan((x-25.4)/381) = 2.4I can't for the life of me figure out how to get Wolfram|Alpha to solve an approximation for this!! Any help would be appreciated. Note: I don't require it to be EXACTLY 2.4, just close!
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Posted 6 months ago
 I assume all your measurements and your x are real numbers.If I can't get Wolfram|Alpha to find when arctan((x-25.4)/381) equals 2.4 I try a plotplot arctan((x-25.4)/381), x= -10^4 to 10^4orLinkToWAand that shows me that your arctan ranges from -pi/2 to pi/2 and that is why it isn't finding a solution when you ask it where that equals 2.4
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Posted 6 months ago
 Thanks,Yes, those are all measurements in millimeters. In the meantime I simply guessed numbers and the closest result to 2.4 degrees is about 1 5/8" or ~41.3mm. I'd love to know how to find it mathematically, however! Thank you for your time.
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Posted 6 months ago
 What do you think about this? angle = ArcTan[a (x - b)] equation = y == Tan[angle] Solve[equation, x] Tan[ArcTan[(x - 25.4)/381]] == Tan[2.4] 
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Posted 6 months ago
 You probably asking for a solution like this: NSolve[ArcTan[(x - 25.4), 381] == 2.4, x] This takes the quadrant into account - refer to the documentation on ArcTan.
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