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How to solve equation with arctan in Wolfram|Alpha?

Matthew Whitney
Posted 5 years ago
POSTED BY: Matthew Whitney
4 Replies
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You probably asking for a solution like this:

NSolve[ArcTan[(x - 25.4), 381] == 2.4, x]

This takes the quadrant into account - refer to the documentation on ArcTan.
POSTED BY: Henrik Schachner

What do you think about this?

angle = ArcTan[a (x - b)]
equation = y == Tan[angle]
Solve[equation, x]

Tan[ArcTan[(x - 25.4)/381]] == Tan[2.4]
POSTED BY: Hans Dolhaine

Thanks,

Yes, those are all measurements in millimeters. In the meantime I simply guessed numbers and the closest result to 2.4 degrees is about 1 5/8" or ~41.3mm. I'd love to know how to find it mathematically, however!

Thank you for your time.
POSTED BY: Matthew Whitney
Bill Nelson
Bill Nelson
Posted 5 years ago

I assume all your measurements and your x are real numbers.

If I can't get Wolfram|Alpha to find when arctan((x-25.4)/381) equals 2.4 I try a plot

plot arctan((x-25.4)/381), x= -10^4 to 10^4

or

LinkToWA

and that shows me that your arctan ranges from -pi/2 to pi/2 and that is why it isn't finding a solution when you ask it where that equals 2.4
POSTED BY: Bill Nelson
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