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Three ParametricPlot3D in one plot

Posted 11 years ago
Hello, how can i do this in the title? i want to see where the three plots are crossing each other.
5 Replies
Thank you very much. I will test it in a little bit.
Yes, i know. I have to change the parameters in order to find 3 fixed points.
There is no guarantee that the three curves will intersect, but you may be able to compute parameters that make them intersect.
In any case, here is an example with curves.
 \[Alpha] = 1; m = 2; \[Lambda] = 0.2; \[Mu] = Log[2]/120;
 p1 = ParametricPlot3D[{(\[Lambda]/\[Mu]*u^m)/(1 + u^m),
    u, (\[Lambda]/\[Alpha]*u^(m - 1)/(1 + u^m) - \[Mu]/\[Alpha])}, {u,
    1, 10}, PlotRange -> {{0, 100}, {1, 10}, {0, .5}}, BoxRatios -> 1,
   PlotStyle -> {Blue, Thickness[0.01]}]
 
 p2 = ParametricPlot3D[{(\[Lambda]/\[Mu]*u^m)/(1 + u^m),
    1, (\[Lambda]/\[Alpha]*u^(m - 1)/(1 + u^m) - \[Mu]/\[Alpha])}, {u,
    1, 10}, BoxRatios -> 1, PlotStyle -> {Red, Thickness[0.01]},
  BoxRatios -> 1]

p3 = ParametricPlot3D[{(\[Lambda]/\[Mu]*u^m)/(1 + u),
   1, (\[Lambda]/\[Alpha]*u^(m - 1)/(1 + u^m) - \[Mu]/\[Alpha])}, {u,
   1, 10}, BoxRatios -> 1, PlotStyle -> {Green, Thickness[0.01]},
  BoxRatios -> 1]

Show[p1, p2, p3]
POSTED BY: W. Craig Carter
i have sth like this
?=1, m=2, ?=0.2, ?= Log[2]/120
ParametricPlot3D[{(?/?*u^m)/(1 + u^m),
  u, (?/?*u^(m - 1)/(1 + u^m) - ?/?)}, {u,
  1, 10}, PlotRange -> {{0, 100}, {1, 10}, {0, 5}}]
and i will have two more. How can i do it.i dont have surfaces. It is only the crossing points between two surfaces.
Here is an example:
surface1[u_, v_] := {Sin[u] Cos[v + u], Cos[v] Sin[u], Cos[u - v]}
surface2[u_, v_] := {Sin[u] Cos[v ], Cos[v] + Sin[u], Cos[u - v]}
surface3[u_, v_] := Pi/3 {Sin[u] Cos[v ], Cos[u] Cos[v], Sin[v]}

ParametricPlot3D[{surface1[u, v], surface2[u, v], surface3[u, v]}, {u,
   0 , 2 Pi}, {v, 0, 2 Pi}, BaseStyle -> Opacity[0.5],
PlotStyle -> {Red, Blue, Green}, Mesh -> None]
POSTED BY: W. Craig Carter
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