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# Three ParametricPlot3D in one plot

Posted 10 years ago
 Hello, how can i do this in the title? i want to see where the three plots are crossing each other.
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Posted 10 years ago
 Thank you very much. I will test it in a little bit.
Posted 10 years ago
 Yes, i know. I have to change the parameters in order to find 3 fixed points.
Posted 10 years ago
 There is no guarantee that the three curves will intersect, but you may be able to compute parameters that make them intersect.In any case, here is an example with curves. \[Alpha] = 1; m = 2; \[Lambda] = 0.2; \[Mu] = Log/120; p1 = ParametricPlot3D[{(\[Lambda]/\[Mu]*u^m)/(1 + u^m),     u, (\[Lambda]/\[Alpha]*u^(m - 1)/(1 + u^m) - \[Mu]/\[Alpha])}, {u,     1, 10}, PlotRange -> {{0, 100}, {1, 10}, {0, .5}}, BoxRatios -> 1,    PlotStyle -> {Blue, Thickness[0.01]}]  p2 = ParametricPlot3D[{(\[Lambda]/\[Mu]*u^m)/(1 + u^m),     1, (\[Lambda]/\[Alpha]*u^(m - 1)/(1 + u^m) - \[Mu]/\[Alpha])}, {u,     1, 10}, BoxRatios -> 1, PlotStyle -> {Red, Thickness[0.01]},   BoxRatios -> 1]p3 = ParametricPlot3D[{(\[Lambda]/\[Mu]*u^m)/(1 + u),    1, (\[Lambda]/\[Alpha]*u^(m - 1)/(1 + u^m) - \[Mu]/\[Alpha])}, {u,    1, 10}, BoxRatios -> 1, PlotStyle -> {Green, Thickness[0.01]},   BoxRatios -> 1]Show[p1, p2, p3]
Posted 10 years ago
 i have sth like this ?=1, m=2, ?=0.2, ?= Log/120ParametricPlot3D[{(?/?*u^m)/(1 + u^m),   u, (?/?*u^(m - 1)/(1 + u^m) - ?/?)}, {u,   1, 10}, PlotRange -> {{0, 100}, {1, 10}, {0, 5}}]and i will have two more. How can i do it.i dont have surfaces. It is only the crossing points between two surfaces.
Posted 10 years ago
 Here is an example:surface1[u_, v_] := {Sin[u] Cos[v + u], Cos[v] Sin[u], Cos[u - v]}surface2[u_, v_] := {Sin[u] Cos[v ], Cos[v] + Sin[u], Cos[u - v]}surface3[u_, v_] := Pi/3 {Sin[u] Cos[v ], Cos[u] Cos[v], Sin[v]}ParametricPlot3D[{surface1[u, v], surface2[u, v], surface3[u, v]}, {u,   0 , 2 Pi}, {v, 0, 2 Pi}, BaseStyle -> Opacity[0.5], PlotStyle -> {Red, Blue, Green}, Mesh -> None]