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How alternate colors in dashed arrows?

POSTED BY: Murray Eisenberg
5 Replies

Or maybe this is a bit better

p1 = {.5, 2};
p2 = {3.7, 4.5};
g1[t_] := p1 (1 - t) + p2 t
pl1 = Graphics[{Red, Arrow[{g1[.1], p1}], Blue, Arrow[{g1[.9], p2}]}];
pl2 = Graphics[{Thick, Red, 
    Table[Line[{g1[2 j/10], g1[(2 j + 1)/10]}], {j, 0, 4}], Blue, 
    Table[Line[{g1[(2 j + 1)/10], g1[(2 j + 2)/10]}], {j, 0, 4}]}];
Show[pl1, pl2]
POSTED BY: Hans Dolhaine

What about this? Not ideal, but a 1st approach

p1 = {.5, 2};
p2 = {3.7, 4.5};
g1[t_] := p1 (1 - t) + p2 t
pl1 = Graphics[{Red, Arrow[{g1[.1], p1}], Blue, Arrow[{g1[.9], p2}]}];
line1 = Graphics[{Red, Dashing[.1], Line[{g1[.1], g1[.9]}]}];
line2 = Graphics[{Blue, Dashing[.05], Line[{g1[.1], g1[.9]}]}];
Show[pl1, line1, line2]
POSTED BY: Hans Dolhaine

Hello Murray,

I guess Dashing[] is well dicussed on SE. Here is just another idea: If the basic problem is to distinguish two arrows which are aligned and only differ in direction, would something like this work for you?

arrw[{p1_, p2_}] := Module[{d, p11, s, p3},
  d = p2 - p1;
  p11 = p1 + .06 d;
  s = Normalize@Reverse[d] {1, -1};
  p3 = Mean[{p1, p2}] + .03 s Norm[d];
  Arrow@BezierCurve[{p11, p3, p2}]
  ]

{p1, p2} = {{1, 2}, {3, 5}};
Graphics[{Arrowheads[.1], Red, arrw[{p1, p2}], Blue, arrw[{p2, p1}]}]

enter image description here

POSTED BY: Henrik Schachner

Thanks to all who replied. The method I'll use is to draw the first arrow solid and then overlay that with the second arrow dashed. This has the desired effect of alternating colors.

POSTED BY: Murray Eisenberg

No, unfortunately, such bowed arrows would not be appropriate. The reason is that the arrows are meant to help visualize a function of the disk to itself (and the inverse of that function), that operates linearly on radii of the disk. Bowed arrows are therefore misleading.

POSTED BY: Murray Eisenberg
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