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Herschel enneahedron

Posted 3 years ago
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POSTED BY: Ed Pegg
2 Replies

Here's the "simpler" form that might work with the rhombic dodecahedron:

points = {{0, 0, 0}, {12, 0, 0}, {0, 0, 12}, {0, 12, 0}, {3, 3, -3}, {3, -3, 3}, {-3, 3, 3}, {9, 9, 3}, {9, 3, 9}, {3, 9, 9}, {8, 8, 8}}/6;
ConvexHullMesh[points]

enter image description here

This could work with the following dodecahedron:

Select[Tuples[Range[-2,2],{3}], MemberQ[{{1,1,1},{0,0,2}},Sort[Abs[#]]]&]
POSTED BY: Ed Pegg

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