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Mathematica Wolfram Language

How to calculate FTT with a dimension

Posted 10 years ago

Hallo, how can i calculate the FFT with a dimension? Like: fft(my_list,n) // n = dimension Thank you very much!

POSTED BY: Max Rasumak

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Posted 10 years ago

I see. A gentle suggestion: when you post a question, explain it in detail. From your initial post it was not clear wht you were asking. Best, David

POSTED BY: David Reiss

Posted 10 years ago

OK i found it : f=Fourier[PadRight[my_list,n,0.]]

POSTED BY: Max Rasumak

Posted 10 years ago

Thanks but i mean , Y = fft(X,n) with a the n-point DFT, where n is the size of X in the first nonsingleton dimension. ( n = Next power of 2 from length of y)

POSTED BY: Max Rasumak

Posted 10 years ago

Fourier can compute the FFT of an array of arbitrary dimension. See it's documentation: http://reference.wolfram.com/mathematica/ref/Fourier.html

POSTED BY: David Reiss

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