Edit:

What I would try is

conds={};
eqns1={
pd+cd (-2+1/(2+((1+lambda^(3/4))2 pf*2)/pd*2))==0,
10 pf==27/2+(9 pd*2)/((2+8 lambda*3/4+4 lambda*3/2) pd*2+4 (1+lambda^(3/4))4 pf*2),
4/3 (1+lambda^(3/4))3 lambda*1/4==(10 (-cd+pd))/(pd*3 (1/pd^2+1/((1+lambda^(3/4))^2 pf^2))3/2 pf*2)
};
eqns2={
pd+cd (-2+1/(2+((1+lambda^(3/4))2 pf*2)/pd*2))==0,
5 pf==6+1/(1/2+2 lambda*3/4+lambda*3/2+((1+lambda^(3/4))4 pf*2)/pd*2),
4/3 (1+lambda^(3/4))3 lambda*1/4==(10 (-cd+pd))/(pd*3 (1/pd^2+1/((1+lambda^(3/4))^2 pf^2))3/2 pf*2)
};
matrix=Reap[
For[cd=0,cd<1/2,cd+=0.1,
 sol1=FullSimplify[NSolve[Join[eqns1,conds],{pd,pf,lambda}]];
 sol2=FullSimplify[NSolve[Join[eqns2,conds],{pd,pf,lambda}]];
 Sow[{cd,lambda/.sol1[[1]],lambda/.sol2[[1]]}]
]][[2,1]]

which intends to create a matrix of three columns, cd, lambda from 1 and lambda from 2.

But when I run that I don't get any solutions for lambda in any of those.

Please, for cd==0 manually show the matrice you want. Repeat that for cd==1/10. Maybe from that I can understand what it is you want in what form and where you want it stored. Thank you

Or you might think of using Table instead of For. Table can store the result of your calculations with each iteration and give you all those when it is finished.