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Data Science Wolfram Language

Replace elements of associations set

Sinval Santos

Posted 2 years ago

I have the following set with two associations: set = {F1[<\|{16, 14, 13} -> 1, {16, 15, 14} -> 1, {17, 18, 20} -> 2, {20, 19, 18} -> 2\|>], F2[<\|{3, 4, 10, 9} -> 3, {10, 4, 2, 8} -> 4, {5, 1, 3, 4} -> 1, {10, 11, 7, 9} -> 5, {5, 11, 7, 1} -> 6, {12, 5, 11, 6} -> 6, {11, 6, 8, 10} -> 5, {1, 3, 9, 7} -> 7, {2, 4, 14, 15} -> 1, {15, 16, 12, 2} -> 1, {12, 16, 13, 5} -> 1, {14, 13, 5, 4} -> 1, {8, 19, 18, 2} -> 2, {8, 19, 20, 6} -> 2, {6, 20, 17, 12} -> 2, {17, 18, 2, 12} -> 2\|>]}; I want to apply, in this set, the following substitutions: news = <\|{16, 14, 13} -> 60, {16, 15, 14} -> 60, {17, 18, 20} -> 70, {20, 19, 18} -> 70, {3, 4, 10, 9} -> 50, {10, 4, 2, 8} -> 50\|>; How to make? I have little experience in operations with associations. Regards, Sinval Attachments: Example.nb

I have the following set with two associations:

set = {F1[<|{16, 14, 13} -> 1, {16, 15, 14} -> 1, {17, 18, 20} -> 
      2, {20, 19, 18} -> 2|>], 
   F2[<|{3, 4, 10, 9} -> 3, {10, 4, 2, 8} -> 4, {5, 1, 3, 4} -> 
      1, {10, 11, 7, 9} -> 5, {5, 11, 7, 1} -> 6, {12, 5, 11, 6} -> 
      6, {11, 6, 8, 10} -> 5, {1, 3, 9, 7} -> 7, {2, 4, 14, 15} -> 
      1, {15, 16, 12, 2} -> 1, {12, 16, 13, 5} -> 1, {14, 13, 5, 4} -> 
      1, {8, 19, 18, 2} -> 2, {8, 19, 20, 6} -> 2, {6, 20, 17, 12} -> 
      2, {17, 18, 2, 12} -> 2|>]};

I want to apply, in this set, the following substitutions:

news = <|{16, 14, 13} -> 60, {16, 15, 14} -> 60, {17, 18, 20} -> 
    70, {20, 19, 18} -> 70, {3, 4, 10, 9} -> 50, {10, 4, 2, 8} -> 50|>;

How to make? I have little experience in operations with associations.

Regards,
Sinval