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Using FilterRules to pass Options from a wrapper function to a Button

Jules Manson

Posted 3 years ago

For the moderators please have patience. I did look through other previously answered posts similar to this but none worked and of course I made several adjustments with my own code and nothing worked. I even tried `ArgumentsOptions` and `CheckArguments` but the docs are very poorly written. It's difficult to determine if they go in the definitions or if an end-user should wrap his functions in them. Below is the standard vanilla method shown in the docs for using `FilterRules`. They use `Plot` I use `Button`. Options[fn1] = {"background" -> Automatic, "color" -> Black, "appearance" -> Automatic, , "label" -> "Echo Chamber", "size" -> {90, 30}}; fn1[opts : OptionsPattern[]] := With[{ bg = OptionValue["background"], col = OptionValue["color"], app = OptionValue["appearance"], lab = OptionValue["label"], siz = OptionValue["size"] }, action[] := Echo["an \"echo chamber\" is one who often repeats unoriginal \ ideas."]; Button[lab, action[], ImageSize -> siz, BaseStyle -> {col}, Appearance -> app, Background -> bg, FilterRules[{opts}, Options[Button]]] ]; (* generates 3: OptionValue: Unknown option Evaluator for fn1 ) ( generates 2: OptionValue: Null is not a valid ) ( but does render a working button ) fn1[Evaluator -> Automatic] ( generates 2: OptionValue: Null is not a valid ) ( but does render a working button ) fn1[] Then I tried a slight variation and that failed too. Options[fn2] = {"background" -> Automatic, "color" -> Black, "appearance" -> Automatic, , "label" -> "Echo Chamber", "size" -> {90, 30}}; fn2[opts : OptionsPattern[]] := With[{ ops = FilterRules[{opts}, Options[Button]], bg = OptionValue["background"], col = OptionValue["color"], app = OptionValue["appearance"], lab = OptionValue["label"], siz = OptionValue["size"] }, action[] := Echo["an \"echo chamber\" is one who often repeats unoriginal \ ideas."]; Button[lab, action[], ImageSize -> siz, BaseStyle -> {col}, Appearance -> app, Background -> bg, If[Length[ops] == 0, Sequence @@ ops, ops]] ]; ( generates 3: OptionValue: Unknown option Evaluator for fn2 ) ( generates 2: OptionValue: Null is not a valid ) ( but does render a working button ) fn2[Evaluator -> Automatic] ( generates 2: OptionValue: Null is not a valid ) ( but does render a working button ) fn2[] What am I doing wrong?*

For the moderators please have patience. I did look through other previously answered posts similar to this but none worked and of course I made several adjustments with my own code and nothing worked. I even tried ArgumentsOptions and CheckArguments but the docs are very poorly written. It's difficult to determine if they go in the definitions or if an end-user should wrap his functions in them.

Below is the standard vanilla method shown in the docs for using FilterRules. They use Plot I use Button.

Options[fn1] = {"background" -> Automatic, "color" -> Black, 
   "appearance" -> Automatic, , "label" -> "Echo Chamber", 
   "size" -> {90, 30}};
fn1[opts : OptionsPattern[]] := With[{
    bg = OptionValue["background"],
    col = OptionValue["color"],
    app = OptionValue["appearance"],
    lab = OptionValue["label"],
    siz = OptionValue["size"]
    },
   action[] := 
    Echo["an \"echo chamber\" is one who often repeats unoriginal \
ideas."];
   Button[lab, action[], ImageSize -> siz, BaseStyle -> {col}, 
    Appearance -> app, Background -> bg, 
    FilterRules[{opts}, Options[Button]]]
   ];
(* generates 3: OptionValue: Unknown option Evaluator for fn1 *)
(* generates 2: OptionValue: Null is not a valid *)
(* but does render a working button *)
fn1[Evaluator -> Automatic]

(* generates 2: OptionValue: Null is not a valid *)
(* but does render a working button *)
fn1[]

Then I tried a slight variation and that failed too.

Options[fn2] = {"background" -> Automatic, "color" -> Black, 
   "appearance" -> Automatic, , "label" -> "Echo Chamber", 
   "size" -> {90, 30}};
fn2[opts : OptionsPattern[]] := With[{
    ops = FilterRules[{opts}, Options[Button]],
    bg = OptionValue["background"],
    col = OptionValue["color"],
    app = OptionValue["appearance"],
    lab = OptionValue["label"],
    siz = OptionValue["size"]
    },
   action[] := 
    Echo["an \"echo chamber\" is one who often repeats unoriginal \
ideas."];
   Button[lab, action[], ImageSize -> siz, BaseStyle -> {col}, 
    Appearance -> app, Background -> bg, 
    If[Length[ops] == 0, Sequence @@ ops, ops]]
   ];
(* generates 3: OptionValue: Unknown option Evaluator for fn2 *)
(* generates 2: OptionValue: Null is not a valid *)
(* but does render a working button *)
fn2[Evaluator -> Automatic]

(* generates 2: OptionValue: Null is not a valid *)
(* but does render a working button *)
fn2[]

What am I doing wrong?

POSTED BY: Jules Manson

2 Replies

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Michael Rogers

Michael Rogers, Emory University

Posted 3 years ago

Cross-posted: https://mathematica.stackexchange.com/questions/273016/using-filterrules-to-pass-options-from-a-wrapper-function-to-a-button-isnt-work

POSTED BY: Michael Rogers

Neil Singer

Neil Singer, AC Kinetics, Inc.

Posted 3 years ago

Jules, Your errors mostly have to do with a blank item in the option list (you have two commas in a row). Additionally, unless you specify that the options of Button are also options of fn1, it will not work. This works: ops = Options[Button]; Options[fn1] = Join[ops, {"background" -> Automatic, "color" -> Black, "appearance" -> Automatic, "label" -> "Echo Chamber", "size" -> {90, 30}}]; fn1[opts : OptionsPattern[]] := With[{bg = OptionValue["background"], col = OptionValue["color"], app = OptionValue["appearance"], lab = OptionValue["label"], siz = OptionValue["size"]}, action[] := Echo["an \"echo chamber\" is one who often repeats unoriginal \ ideas."]; Button[lab, action[], ImageSize -> siz, BaseStyle -> {col}, Appearance -> app, Background -> bg, FilterRules[{opts}, Options[Button]]]]; fn1[Evaluator -> Automatic] fn1[] Regards, Neil

Jules,

Your errors mostly have to do with a blank item in the option list (you have two commas in a row). Additionally, unless you specify that the options of Button are also options of fn1, it will not work.

This works:

ops = Options[Button];
Options[fn1] = 
  Join[ops, {"background" -> Automatic, "color" -> Black, 
    "appearance" -> Automatic, "label" -> "Echo Chamber", 
    "size" -> {90, 30}}];
fn1[opts : OptionsPattern[]] := 
  With[{bg = OptionValue["background"], col = OptionValue["color"], 
    app = OptionValue["appearance"], lab = OptionValue["label"], 
    siz = OptionValue["size"]}, 
   action[] := 
    Echo["an \"echo chamber\" is one who often repeats unoriginal \
ideas."];
   Button[lab, action[], ImageSize -> siz, BaseStyle -> {col}, 
    Appearance -> app, Background -> bg, 
    FilterRules[{opts}, Options[Button]]]];

fn1[Evaluator -> Automatic]


fn1[]

Regards,

Neil

POSTED BY: Neil Singer

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