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New Method for SumConvergence: if grouping of series is divergent so is original series

Posted 2 years ago
POSTED BY: ZAQU zaqu
5 Replies
Posted 1 year ago
POSTED BY: ZAQU zaqu
Posted 1 year ago
POSTED BY: ZAQU zaqu
Posted 1 year ago

BTW, I made a typo when I wrote the post:

Then simple but a little obscure rule in calculus says that then the original series can be only divergent.

I edited to divergent.

If you have convergent series its groupings can be only convergent, and if any series is divergent its groupings can be divergent and convergent.

POSTED BY: ZAQU zaqu
Posted 1 year ago

You can plug in your own method into SumConvergence. Here's a start. Adapt as desired.

groupTermsCheck // ClearAll;
groupTermsCheck[nTerms_, OptionsPattern[]][expr_, k_] := Module[{j},
   SumConvergence[expr, k] &&
    SumConvergence[Sum[expr, {k, nTerms*j, nTerms*j + nTerms - 1}], j]
   ];
groupTermsCheck[expr_, k_] := groupTerms[2][expr, k];

SumConvergence[(-1)^(n)/(Sqrt[n] + (-1)^n), n, 
 Method -> groupTermsCheck[2]]
(*  False  *)
POSTED BY: Updating Name
Posted 1 year ago

Bad idea? I think my idea is cool.

POSTED BY: ZAQU zaqu
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