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Mathematics Wolfram Language

Posted 2 years ago

For polynomials： -x1 - x2 - 1/(x1 \[Lambda] + x2 \[Mu]) + 2 (x1 \[Lambda] + x2 \[Mu]) + (Log[x1] - Log[x2])/(x1 - x2) to get the result: (x1 - x2) (-1 + 2 \[Lambda]) - 1/(x1 \[Lambda] + x2 \[Mu]) + ( Log[x1] - Log[x2])/(x1 - x2) Why can't we handle it using this method? -x1 - x2 - 1/(x1 \[Lambda] + x2 \[Mu]) + 2 (x1 \[Lambda] + x2 \[Mu]) + (Log[x1] - Log[x2])/(x1 - x2) // Collect[#, {x1, x2}] &

For polynomials：

-x1 - x2 - 1/(x1 \[Lambda] + x2 \[Mu]) + 
 2 (x1 \[Lambda] + x2 \[Mu]) + (Log[x1] - Log[x2])/(x1 - x2)

to get the result:

(x1 - x2) (-1 + 2 \[Lambda]) - 1/(x1 \[Lambda] + x2 \[Mu]) + (
 Log[x1] - Log[x2])/(x1 - x2)

Why can't we handle it using this method?

-x1 - x2 - 1/(x1 \[Lambda] + x2 \[Mu]) + 
  2 (x1 \[Lambda] + x2 \[Mu]) + (Log[x1] - Log[x2])/(x1 - x2) // 
 Collect[#, {x1, x2}] &

POSTED BY: Lee Tao

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Posted 2 years ago

If you're going to post the same question on multiple sites, please make that known. Otherwise, you might be wasting the time of folks trying to help you if there's already an answer or a strong hint at another site.

POSTED BY: Jim Baldwin

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