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Mathematics Equation Solving Symbolic Computations

Finding Upper Bounds on Complex Function Extrema

Patrick DS.

Posted 3 days ago

Hello together, I am new to Mathematica and would like to find an upper bound on the number of extrema for a complex function, defined in terms of the variable h: `g[h, l, d]:=100sqrt[((cos[d]sin[h]/arccos[cos[d]cos[h]cos[l] + sin[d]*sin[l]] + ...;` The formula here is abbreviated since it’s quite large. I've attempted to find possible extrema in terms of h using: Solve[{D[g[h],h]==0},h]; However, Solve is not capable to find any solution. What else can I try? Thank you very much for your help in advance. :-) Greetings, Patrick

POSTED BY: Patrick DS.

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Henrik Schachner

Henrik Schachner, Radiation Therapy Center, Weilheim, Germany

Posted 3 days ago

What else can I try? Well, a good start could be to use a correct syntax! Mathematica is case sensitive!, So, your function definition should rather read like so: g[h_, l_, d_] := 100Sqrt[((Cos[d]Sin[h]/ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]*Sin[l]] + ...))]; And then you can try to call Solve[{D[g[h,l,d],h]==0},h]; because a function `g[h]` is not defined.

POSTED BY: Henrik Schachner

Patrick DS.

Posted 17 hours ago

Thank you for your response. I’ve corrected the syntax and attempted to derive the function with respect to h. This function is the general form of the one I presented previously: f[h_,l_,d_,x_,y_]:=Sqrt[(200Sqrt[-Cos[d]^2Cos[h]^2Cos[l]^2 - 2Cos[d]Cos[h]Cos[l]Sin[d]Sin[l] - Sin[d]^2Sin[l]^2 + 1](Cos[d]^2Cos[h]Cos[l]Sin[h] + Cos[d]Sin[d]Sin[h]Sin[l])xArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2 + 10000(Cos[d]^2Cos[h]^2Cos[l]^2 + 2Cos[d]Cos[h]Cos[l]Sin[d]Sin[l] + Sin[d]^2Sin[l]^2 - 1)ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^3 + ((Cos[d]^2Cos[h]^2Cos[l]^2 + 2Cos[d]Cos[h]Cos[l]Sin[d]Sin[l] + Sin[d]^2Sin[l]^2 - 1)ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^3 - (2Cos[d]^4Cos[h]^2Cos[l]^2Sin[h]^2 + 4Cos[d]^3Cos[h]Cos[l]Sin[d]Sin[h]^2Sin[l] + 2Cos[d]^2Sin[d]^2Sin[h]^2Sin[l]^2 - Cos[d]^2Sin[h]^2)ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]])x^2 - ((Cos[d]^2Cos[h]^2Cos[l]^2 + 2Cos[d]Cos[h]Cos[l]Sin[d]Sin[l] + Sin[d]^2Sin[l]^2)ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^3 - (2Cos[d]^4Cos[h]^2Cos[l]^2Sin[h]^2 + 4Cos[d]^3Cos[h]Cos[l]Sin[d]Sin[h]^2Sin[l] + 2Cos[d]^2Sin[d]^2Sin[h]^2Sin[l]^2 - Cos[d]^2Sin[h]^2)ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]])y^2 - 2(100Sqrt[-Cos[d]^2Cos[h]^2Cos[l]^2 - 2Cos[d]Cos[h]Cos[l]Sin[d]Sin[l] - Sin[d]^2Sin[l]^2 + 1](Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l])Sqrt[-(Cos[d]^2Sin[h]^2 - ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2)/ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2]ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^3 + ((Cos[d]^3Cos[h]^2Cos[l]^2Sin[h] + 2Cos[d]^2Cos[h]Cos[l]Sin[d]Sin[h]Sin[l] + Cos[d]Sin[d]^2Sin[h]Sin[l]^2 - Cos[d]Sin[h])(-(Cos[d]^2Sin[h]^2 - ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2)/ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2)^(3/2)ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2 + (Cos[d]^5Cos[h]^2Cos[l]^2Sin[h]^3 + 2Cos[d]^4Cos[h]Cos[l]Sin[d]Sin[h]^3Sin[l] + Cos[d]^3Sin[d]^2Sin[h]^3Sin[l]^2 - Cos[d]^3Sin[h]^3 - (3Cos[d]^3Cos[h]^2Cos[l]^2Sin[h] + 6Cos[d]^2Cos[h]Cos[l]Sin[d]Sin[h]Sin[l] + 3Cos[d]Sin[d]^2Sin[h]Sin[l]^2 - 2Cos[d]Sin[h])ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2)Sqrt[-(Cos[d]^2Sin[h]^2 - ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2)/ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^2])x)y)/((Cos[d]^2Cos[h]^2Cos[l]^2 + 2Cos[d]Cos[h]Cos[l]Sin[d]Sin[l] + Sin[d]^2Sin[l]^2 - 1)ArcCos[Cos[d]Cos[h]Cos[l] + Sin[d]Sin[l]]^3)]; solutions = Solve[{D[f[h,l,d,x,y],h]==0, -Pi < l, l < Pi, -Pi/4 < d, d < Pi/4}, h]; However, Solve and Reduce do not produce useful outputs or do not halt. Is there an automated way to detect substitution patterns, or could I use a mathematical trick to estimate the upper bound on the number of extrema for any initial values of l,d,x,y with l∈[−π,π] and d∈[−π/4,π/4]?

Thank you for your response. I’ve corrected the syntax and attempted to derive the function with respect to h. This function is the general form of the one I presented previously:

f[h_,l_,d_,x_,y_]:=Sqrt[(200*Sqrt[-Cos[d]^2*Cos[h]^2*Cos[l]^2 - 2*Cos[d]*Cos[h]*Cos[l]*Sin[d]*Sin[l] - Sin[d]^2*Sin[l]^2 + 1]*(Cos[d]^2*Cos[h]*Cos[l]*Sin[h] + Cos[d]*Sin[d]*Sin[h]*Sin[l])*x*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2 + 10000*(Cos[d]^2*Cos[h]^2*Cos[l]^2 + 2*Cos[d]*Cos[h]*Cos[l]*Sin[d]*Sin[l] + Sin[d]^2*Sin[l]^2 - 1)*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^3 + ((Cos[d]^2*Cos[h]^2*Cos[l]^2 + 2*Cos[d]*Cos[h]*Cos[l]*Sin[d]*Sin[l] + Sin[d]^2*Sin[l]^2 - 1)*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^3 - (2*Cos[d]^4*Cos[h]^2*Cos[l]^2*Sin[h]^2 + 4*Cos[d]^3*Cos[h]*Cos[l]*Sin[d]*Sin[h]^2*Sin[l] + 2*Cos[d]^2*Sin[d]^2*Sin[h]^2*Sin[l]^2 - Cos[d]^2*Sin[h]^2)*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]])*x^2 - ((Cos[d]^2*Cos[h]^2*Cos[l]^2 + 2*Cos[d]*Cos[h]*Cos[l]*Sin[d]*Sin[l] + Sin[d]^2*Sin[l]^2)*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^3 - (2*Cos[d]^4*Cos[h]^2*Cos[l]^2*Sin[h]^2 + 4*Cos[d]^3*Cos[h]*Cos[l]*Sin[d]*Sin[h]^2*Sin[l] + 2*Cos[d]^2*Sin[d]^2*Sin[h]^2*Sin[l]^2 - Cos[d]^2*Sin[h]^2)*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]])*y^2 - 2*(100*Sqrt[-Cos[d]^2*Cos[h]^2*Cos[l]^2 - 2*Cos[d]*Cos[h]*Cos[l]*Sin[d]*Sin[l] - Sin[d]^2*Sin[l]^2 + 1]*(Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l])*Sqrt[-(Cos[d]^2*Sin[h]^2 - ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2)/ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2]*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^3 + ((Cos[d]^3*Cos[h]^2*Cos[l]^2*Sin[h] + 2*Cos[d]^2*Cos[h]*Cos[l]*Sin[d]*Sin[h]*Sin[l] + Cos[d]*Sin[d]^2*Sin[h]*Sin[l]^2 - Cos[d]*Sin[h])*(-(Cos[d]^2*Sin[h]^2 - ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2)/ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2)^(3/2)*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2 + (Cos[d]^5*Cos[h]^2*Cos[l]^2*Sin[h]^3 + 2*Cos[d]^4*Cos[h]*Cos[l]*Sin[d]*Sin[h]^3*Sin[l] + Cos[d]^3*Sin[d]^2*Sin[h]^3*Sin[l]^2 - Cos[d]^3*Sin[h]^3 - (3*Cos[d]^3*Cos[h]^2*Cos[l]^2*Sin[h] + 6*Cos[d]^2*Cos[h]*Cos[l]*Sin[d]*Sin[h]*Sin[l] + 3*Cos[d]*Sin[d]^2*Sin[h]*Sin[l]^2 - 2*Cos[d]*Sin[h])*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2)*Sqrt[-(Cos[d]^2*Sin[h]^2 - ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2)/ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^2])*x)*y)/((Cos[d]^2*Cos[h]^2*Cos[l]^2 + 2*Cos[d]*Cos[h]*Cos[l]*Sin[d]*Sin[l] + Sin[d]^2*Sin[l]^2 - 1)*ArcCos[Cos[d]*Cos[h]*Cos[l] + Sin[d]*Sin[l]]^3)];

solutions = Solve[{D[f[h,l,d,x,y],h]==0, -Pi < l, l < Pi, -Pi/4 < d, d < Pi/4}, h];

However, Solve and Reduce do not produce useful outputs or do not halt. Is there an automated way to detect substitution patterns, or could I use a mathematical trick to estimate the upper bound on the number of extrema for any initial values of l,d,x,y with l∈[−π,π] and d∈[−π/4,π/4]?

POSTED BY: Patrick DS.

Gianluca Gorni

Gianluca Gorni, University of Udine

Posted 13 hours ago

Since you are looking for extrema, I would perhaps remove the `Sqrt` that envelops the function. Even then, the problem seems too complicated to be solved symbolically. I would make some conjectures based on numerical data, like this: Table[Length[Union@NSolve[{D[f[h, l, d, 1, 1], h] == 0, -Pi < h < Pi}, h, Reals]], {l, -Pi, Pi, Pi/2}, {d, -Pi/4, Pi/4, Pi/8}]

POSTED BY: Gianluca Gorni

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