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Converting from Cartesian into cylindrical coordinates

Posted 4 months ago
POSTED BY: Mitchell Sandlin
2 Replies

ToPolarCoordinates in 3 dimensions gives hyperspherical coordinates, not cylindrical. You mention a differential equation, but I cannot see any differential equation in your calculation. You can visualize your integral this way:

reg = ImplicitRegion[0 < x < 1 &&
   -Sqrt[1 - x^2] < y < Sqrt[1 - x^2] &&
   Sqrt[x^2 + y^2] < z < 1,
  {x, y, z}];
% // Region
Volume[reg]
Integrate[1, Element[{x, y, z}, reg]]
POSTED BY: Gianluca Gorni

Thanks, your response helped.

As an aside, I am not sure where the word differential came from, and you are correct in that my request really has nothing to do with differential equations.

Thanks Again,

Mitch Sandlin

POSTED BY: Mitchell Sandlin
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