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# Series bug for ParabolicCylinderD ?

Posted 9 years ago
 Series gives two different results at the leading $Sqrt[1/x]$ term... The second is the correct one.
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Posted 9 years ago
 Find Series[x^(1/2)D] then multiply by x^(-1/2): In[1]:= Series[ x^(1/2) ParabolicCylinderD[-(1/2), (-1 + I) x], {x, \[Infinity], 0}] In[2]:= Series[ x^(1/2) ParabolicCylinderD[-(1/2), (-1 + I) x], {x, \[Infinity], 1}] You get same result for both inputs.
Posted 9 years ago
 Thanks for the reply,Of course things look less dramatic when you know the correct result, and then you can find ways around, but we were that close to publish a paper which includes a garbage result... It is a bug! The first result is wrong in three respects: No O(1) corrections. Half of the O(x^{-1/2}) term is missing. While O(x^{-1}) is present, no O(x^{-1/2}) corrections are mentioned.
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