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Finding the exact range of a function involving exponential and quadratic terms

Posted 2 days ago
POSTED BY: Wen Dao
2 Replies

This shows that the function has only one stationary point, which is a local minimum, with a value of Sqrt[2]:

f = y^2/4 + Sqrt[(x - y^2/4)^2 + (E^x - y)^2] + 1;
grad = D[f, {{x, y}}];
stationary = Solve[grad == 0, {x, y}, Reals]
f /. stationary[[1]] // FullSimplify
hess = D[grad, {{x, y}}] /. stationary[[1]] // FullSimplify;
Eigenvalues[hess] // N
POSTED BY: Gianluca Gorni

I have only:

POSTED BY: Mariusz Iwaniuk
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