b^2 x x0 - b^2 x0^2 + a^2 y y0 - a^2 y0^2 == 0
How to simultaneously shift the terms containing x₀² and y₀² from the left-hand side of the equation,get the result as follows:What other good methods are there?
b^2 x x0 + a^2 y y0 == b^2 x0^2 + a^2 y0^2
The follows is my own method.
b^2 x x0 - b^2 x0^2 + a^2 y y0 - a^2 y0^2 == 0
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b^2 x x0 - m_.*b^2 x0^2 + a^2 y y0 - n_.*a^2 y0^2 == 0 :>
b^2 x x0 + a^2 y y0 == m*b^2 x0^2 + n*a^2 y0^2
