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If someone could tell me how on mathematica you do this thanks?

Anonymous User
Anonymous User
Posted 10 years ago

FInd the exact expression for the Sine of the angle between vectors <2,-1,1> and <3,2,1>.

POSTED BY: Anonymous User
2 Replies

Now stuff has become so easy ...

In[3]:= Sin[VectorAngle[{2, -1, 1}, {3, 2, 1}]]
Out[3]= Sqrt[59/21]/2

VectorAngle and the formula is of course

In[4]:= Sin[ArcCos[Dot[{2, -1, 1}, {3, 2, 1}]/(Norm[{2, -1, 1}] Norm[{3, 2, 1}])]]
Out[4]= Sqrt[59/21]/2

as the help spells it out.

POSTED BY: Udo Krause

Calculate the cross product with Cross and go from there.

http://en.wikipedia.org/wiki/Cross_product

POSTED BY: Frank Kampas
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