Message Boards Message Boards

0
|
2529 Views
|
2 Replies
|
1 Total Likes
View groups...
Share
Share this post:
GROUPS:

If someone could tell me how on mathematica you do this thanks?

Anonymous User
Anonymous User
Posted 11 years ago

FInd the exact expression for the Sine of the angle between vectors <2,-1,1> and <3,2,1>.

POSTED BY: Anonymous User
2 Replies

Calculate the cross product with Cross and go from there.

http://en.wikipedia.org/wiki/Cross_product

POSTED BY: Frank Kampas

Now stuff has become so easy ...

In[3]:= Sin[VectorAngle[{2, -1, 1}, {3, 2, 1}]]
Out[3]= Sqrt[59/21]/2

VectorAngle and the formula is of course

In[4]:= Sin[ArcCos[Dot[{2, -1, 1}, {3, 2, 1}]/(Norm[{2, -1, 1}] Norm[{3, 2, 1}])]]
Out[4]= Sqrt[59/21]/2

as the help spells it out.

POSTED BY: Udo Krause
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract