Limit[-3 x + 3 Log[-1 + E^x], x -> Infinity] How can the answer 0 be found ? (Log is natural logarithm)
Quite easy to explain in simple words:
-1+E^x tends to E^x for large x. So Log[E^x] = x for large x, what you are left with is -3x + 3x = 0
Thanks !