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Anonymous User

How exactly would you do this on mathematica

Anonymous User
Posted 9 years ago
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For which values of a will the following systems of linear equations have no solutions, one solution , or an infinite number of solutions? x+2y-3z=4 2x-y+5z=2 4x+3y+a^2z=a+3

POSTED BY: Anonymous User

Several functions in Mathematica can do it. Example: use the Reduce function:

Reduce[{x + 2 y - 3 z == 4 2 x - y + 5 z == 2 4 x + 3 y + a^2 z == a + 3}, {x, y, z}]

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From the result you should always get the linear system solvable for $a \in \mathbb{R}$

POSTED BY: Shenghui Yang
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