Hi everyone, I'm trying to find the trajectory of an electron in a graphene lattice. I've a set of three differential equations in the three directions mx''=Fx,my''=Fy,mz''=Fz and i try to solve my system whith NDSolve and to plot the result, but what I have in output is the same linear function whatever are boundary conditions. It's clear that it's not a right solution, so could you help me to understand what I'm doing wrong? Here's my code:
Clear["Global`*"]
coordx = {0.6327, 1.88058, 3.03927, 4.28716, 5.44584, 6.69373,
7.85241, 9.10029, 1.9728, 3.22069, 4.37937, 5.62726, 6.78594,
8.03382, 9.19251, 10.4404, 3.3129, 4.56079, 5.71947, 6.96736,
8.12604, 9.37393, 10.53261, 11.7805, 4.653, 5.90089, 7.05956,
8.30746, 9.46614, 10.71403, 11.87271, 13.1206};
coordy = {1.31579, 1.79441, 0.98308, 1.46168, 0.65035, 1.12896,
0.31763, 0.79624, 3.08485, 3.56345, 2.75213, 3.23074, 2.41941,
2.89802, 2.08669, 2.56529, 4.8539, 5.33251, 4.52119, 4.99979,
4.18846, 4.66707, 3.85574, 4.33435, 6.62295, 7.10157, 6.29024,
6.76884, 5.95751, 6.43613, 5.62479, 6.10341};
coordz = {3.01288, 2.54181, 2.65281, 2.18174, 2.29275, 1.82168,
1.93268, 1.46161, 1.95888, 1.4878, 1.5988, 1.12774, 1.23874,
0.76767, 0.87868, 0.4076, 0.90487, 0.43379, 0.5448, 0.07373,
0.18473, -0.28634, -0.17533, -0.64641, -0.14914, -0.62022, \
-0.5092, -0.98028, -0.86927, -1.34035, -1.22934, -1.70042};
me = 9.01*10^-31;
pi = 3.14159;
epsilon0 = 8.854*10^-12;
q = -1.6*10^-19;
Q = 1.6*10^-19;
step = 0.01;
Forzax[p_, r_] :=
Sum[(Q*q)/(4 pi*epsilon0*Norm[r - p[[i]]]^2), {i, Length[p]}]
Forzay[p_, r_] :=
Sum[(Q*q)/(4 pi*epsilon0*Norm[r - p[[i]]]^2), {i, Length[p]}]
Forzaz[p_, r_] :=
Sum[(Q*q)/(4 pi*epsilon0*Norm[r - p[[i]]]^2), {i, Length[p]}]
step = 0.01;
sol = NDSolve[{x''[t] - Forzax[coordx, {x[t]}]/me == 0,
y''[t] - Forzay[coordy, {y[t]}]/me == 0,
z''[t] - Forzaz[coordz, {z[t]}]/me == 0, x[0] == 0, y[0] == -5,
z[0] == -4, x'[0] == 1, y'[0] == 2, z'[0] == 0}, {x[t], y[t],
z[t]}, {t, 0, 15000}]
Show[ParametricPlot3D[
Evaluate[{x[t], y[t], z[t]} /. sol], {t, 0, 15000},
PlotRange -> All]]
Thank you in advance. Regards Filippo