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Trouble with rules

Posted 11 years ago
POSTED BY: larry davis
2 Replies
POSTED BY: Daniel Lichtblau
In[2]:= Limit[Exp[a*r]/Exp[r], r -> \[Infinity], 
 Assumptions -> {Abs[a] < 1}]

Out[2]= 0
POSTED BY: Frank Kampas
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