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Complex numbers: i vs I

Posted 11 years ago
In[8]:= (1 + I)* (1 - 3 I)      <===== upper case

Out[8]= 4 - 2 i       <=======  lower case

With upper case I in In, it works, but uses the lower case i in Out.

In[11]:= (1 + i)*(1 - 3 i)    <==== lower case

Out[11]= (1 - 3 i) (1 + i)   <===== not multiply?

With lower case i in IN, it doesn't Works.

It seems inconsistent (or not?)

thanks in advance.

POSTED BY: rionilo
5 Replies
Posted 11 years ago
POSTED BY: David Keith
Posted 11 years ago

Thanks to everyone for their answers. I understand, however, why if I write (1+ii) (3-ii) Mathematica replies 4 + 2i (only i)? Only when I change the output Font size appears 4 + 2ii. Should not keep Mathematica the input format (if input I output I, if input ii output ii,...)?

Note: ii = Esc ii Esc

Thanks again.

POSTED BY: rionilo

It does not display as just i. It is displaying as the esc-ii-esc but the resolution of your screen is blurring the character so you think it is just an i. Use the magnification popup on the lower right hand side of the notebook to increase the magnification to see this.

Read this to understand this better:

http://reference.wolfram.com/language/ref/I.html

POSTED BY: David Reiss

The Out statement uses a special, somewhat italicized, lower case i that you can find in the Basic Math Assistant palette.

The same is true for lower case e.

Lower case i is just the symbol i. Often used as a summation index. Imaginary unit is written capitol I.

POSTED BY: S M Blinder
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