Hi David,
I'm confused. In the text lead in you give dy/dt as a function of y and x, with an initial condition for y. Since you use dy/dt, and y depends on a scalar initial condition, y must be y[t], but what is x? Is this a constant in an ordinary diffeq?
In In[177] below, dy/dt becomes dy/dx. Now there is only one independent variable which is x, and an ordinary diffeq?
Am I missing something?
Best,
David