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Initial Value Problem Questions

POSTED BY: David Arnold
4 Replies
Posted 11 years ago
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POSTED BY: David Keith

Absolutely amazing answer. You are the first ever to show me a concrete example of how to use the Reduce command.

POSTED BY: David Arnold
Posted 11 years ago

Hi David,

I'm confused. In the text lead in you give dy/dt as a function of y and x, with an initial condition for y. Since you use dy/dt, and y depends on a scalar initial condition, y must be y[t], but what is x? Is this a constant in an ordinary diffeq?

In In[177] below, dy/dt becomes dy/dx. Now there is only one independent variable which is x, and an ordinary diffeq?

Am I missing something?

Best,

David

POSTED BY: David Keith

No, my fault. I've tried to edit everything, changing all the x's to t's.

POSTED BY: David Arnold
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