# The system of equations with two variables.

Posted 9 years ago
6233 Views
|
4 Replies
|
1 Total Likes
|
 Good afternoon! More recently started to learn the language Mathematica, decided to use it to solve one of the equations given scientific director at the university. I have the equation of the type (attached image). Tried to implement it in Mathematica 10, but the result (graph) is not very similar to the truth. The question arises: mathematically, I (sort of) correctly described the equation, but the answer is clearly not what it should be. Tell me, what could be the problem? In order Bessel equation used 0 , 1, 2. eps1=eps2=0.5 k=3 beta=0,999 I enclose a picture - should look like the graph .Sorry for my English, I use Google translator. Kind regards, Denis Attachments:
4 Replies
Sort By:
Posted 9 years ago
 Thank you, and a graph of the truth has become smoother. The question is precisely what can be wrong? I suspect that in the condition I have given the first derivative "Bessel K" and others. I outlined them in the right code? Another question is this. On my system, the variable "R" changes in the gap [0;25] and the variables "Kz" are changed from [0;3.1]. Tried to build a separate S1-S6 and the program does not give me the addiction. I do not understand, it seems the problem in the code. The question is whether I even brought it? For the first time use wolfram mathematica mistakes can be very trivial. If not difficult, review of the at least one "S" may be wrong, I just laid out code. Kind regards, Denis.
Posted 9 years ago
 If I understand correctly, the file is not opened because the name is not on the English keyboard layout. I'm attaching a corrected version,Kind regards, Denis. Attachments:
Posted 9 years ago
 Fine. With the default options which you are using the graphics comes out quite irregularly. But adding the options PlotPoints->100 turns it into a system of smooth curves. This, however, does not match your graphics quantitatively. I guess that your definition of S1 ... S6 does not exactly match the form which underlies your graphics. Hope this helps.
Posted 9 years ago
 Denis, please provide the Mathematica code which gave you a graph which you compared to the one of your figure. Aha! You did already, but my English speaking version of Mathematica does not open a file with a name containing kyrillic letters.