Group Abstract Group Abstract

Message Boards Message Boards

0
|
10.1K Views
|
4 Replies
|
4 Total Likes
View groups...
Share
Share this post:
GROUPS:

ZTransform of a sequence that changes its explicit formula

Posted 11 years ago

Hi, i was trying to calculate the Zeta-Transform of a sequence that changes its explicit formula, for example:

x(n)= n  for  n=2k
x(n) = 1/n for n=2k+1 

How could I do?

POSTED BY: Luca Pirozzi
4 Replies
Posted 11 years ago

Sorry for the post-format, but i had to write quite quickly. Thank you very much for the reply, it really helped and solved the problem.

POSTED BY: Luca Pirozzi
POSTED BY: Daniel Lichtblau
Posted 11 years ago

Thanks for replying, so should i write as input:

ZTransform[x^((-1)^n), n, z] 
(* Out[342]= (z (1 + x^2 z))/(x (-1 + z^2)) *)

? If i do so, Wolfram doesn't compute it, trying to solve

342=(z (1 + x^2 z))/(x (-1 + z^2)) 

as an equation. As example, how could I write this? enter image description here

POSTED BY: Luca Pirozzi

In this case there is a closed form for the input and ZTransform seems to handle it.

ZTransform[x^((-1)^n), n, z]

(* Out[342]= (z (1 + x^2 z))/(x (-1 + z^2)) *)
POSTED BY: Daniel Lichtblau
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard